Order from least to greatest by using <: -3^2; 3^2; -3^-2; 3^-2 Thanks :)
negative less than positive
-3^2 and -3^-2 are minimum and 3^2 and 3^-2 will be max
now we have to arrange in order
if power is negative than take reciprocal or revese the number like x^-2=1/x^2
can u do it now ??
one approach is to find the value of each and place on the number line (-3)^2 = (-3)(-3) = (3)^2 =(3)(3) = (-3)^-2 = (-3)^0(-3)^-2 =1/(-3)^2=1/(-3)(-3)= (3)^-2 = 1/(3)(3) =
was that all of the question?
@ButterflyHope Did you get an answer to this question?
Yes sorry, thanks @triciaal and @gorv
Here are the numbers in the order you listed them: \(-3^2 = -(3^2) = - 9\) \(3^2 = 9\) \(-3^{-2} = -(3^{-2}) = - \dfrac{1}{3^2} = - \dfrac{1}{9} \) \(3^{-2} = \dfrac{1}{3^2} = \dfrac{1}{9}\) The order is: \(-3^2 \lt -3^{-2} \lt 3^{-2} \lt 3^2\)
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