How to start??
Calculate the enthalpy of the reaction
4B(s)+3O2(g)→2B2O3(s)
given the following pertinent information:
B2O3(s)+3H2O(g)→3O2(g)+B2H6(g), ΔrH∘A=+2035 kJ mol−1
2B(s)+3H2(g)→B2H6(g), ΔrH∘B=+36 kJ mol−1
H2(g)+12O2(g)→H2O(l), ΔrH∘C=−285 kJ mol−1
H2O(l)→H2O(g), ΔrH∘D=+44 kJ mol−1

Question

How to start??
Calculate the enthalpy of the reaction
4B(s)+3O2(g)→2B2O3(s)
given the following pertinent information:
B2O3(s)+3H2O(g)→3O2(g)+B2H6(g),   ΔrH∘A=+2035  kJ mol−1
2B(s)+3H2(g)→B2H6(g),                        ΔrH∘B=+36  kJ mol−1
H2(g)+12O2(g)→H2O(l),                     ΔrH∘C=−285  kJ mol−1
H2O(l)→H2O(g),                                    ΔrH∘D=+44  kJ mol−1

cuanchi · Answer

arrange the equations so the reactants and or the product are in the same side as in the reaction that you want to find the enthalpy for

cuanchi · Answer

for example the first reaction has to be reverted, with the B2O3 in the products side

toxicsugar22 · Answer

cuanchi help me please