Question

Consider the line -6x+8y=9
.
Find the equation of the line that is perpendicular to this line and passes through the point -3,-2


Find the equation of the line that is parallel to this line and passes through the point -3,-2

Answer 1

Convert the line to slope intercept form

Answer 2

how ?

Answer 3

-6x+8y=9
8y=6x+9

Answer 4

\[y=\frac{ 3 }{ 4 }x+\frac{ 9 }{ 8 }\]

Answer 5

The slope would be 3/4

Answer 6

okay i got -3/4 ?

Answer 7

What would be the slope of a line perpendicular to this line?

Answer 8

It's not negative..

Answer 9

I see where i got it wrong

Answer 10

ok now a line that is perpendicular has the negative reciprocal of this slope
which is -4/3

Answer 11

where did you get -4/3 ???

Answer 12

ok let's go a little slower..

Answer 13

you flipped the equation ?
but how does it become negative ?

Answer 14

perpendicular lines have the negative opposite of the other slope..

Example: What is the perpendicular slope of 2?

Answer 15

-2 ?

Answer 16

Close.. -1/2

Answer 17

;/

Answer 18

You have to flip the number and make it negative

Answer 19

oh okay

Answer 20

Do you understand a little better?

Answer 21

yes

Answer 22

ok so now that we have the perpendicular slope which is -4/3.. we can plug it into the point slope form which is

\[Y-Y _{1}=m(x-x _{1})\]

Answer 23

\[y+2=-\frac{ 4 }{ 3 }(x+3)\]

Answer 24

solve for y