What point in the feasible region maximizes P for the objective function P = 2x + 3y? Constraints: 2x+y≤15 x+3y≤20 x≥0, y≥0 ive tried for so long but i have no idea.. answer choices: A. (0,15) B. (5,5) C. (8,7) D. (2,6)
are you able to graph the inequalities?
yes, I did that but i think i might of done it wrong..
can you draw it out?
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this is what I got. I'm not sure if it's right becasue arent the intersection points supposed to be the answers?
that's a good rough sketch, so you have the right graph where does each line intersect? In other words, what are the vertices of the boundaries?
the intersections are the testng points yes
the points from the intersections were not apart of the answer choices though , so i don't know what to do
now, if the options given are not a point of intersection, then you simply want to choose the one that is in the boundaries and makes P maximal
all of the answer choices are like 6.6666 for x or 5.76 or some not whole number and in the answer choices, all the numbers are whole
we can tell if a point is in the feasible region if it meets all of the constraints
for example: 0,15 is fine for eq1, but fails for eq2 ... its not in the region
so it doesn't have to be the exact intersecting point? it can just be in the intersection region?
its asking which option is in the feasible region, and maximizes P
first step, determine which options are in the feasible region, then test them out for maximum
Ohh okay, thank you!!
A and C do not meet the criterias, so we need to test the remaining points
I think it's b??
10+15 is bigger then 4+18 yeah
okay great, thanks so much
youre welcome
Here is the graph (I used Geogebra, which you can download for free) Evaluate P at each "intersection point" point (5,5) maximizes P= 2x+3y= 10+15= 25
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