Given (1, 1) is a point on the base graph of f(x) = x^5 and g(x) = -(x + 1)5 − 5, find where the point on f(x) would be moved to on the graph of g(x).

Question

Given (1, 1) is a point on the base graph of f(x) = x^5 and  g(x) = -(x + 1)5 − 5, find where the point on f(x) would be moved to on the graph of g(x).

darkbluechocobo · Answer

would this be 1,-5?

cwrw238 · Answer

g(x)  = - (x + 1)^5 - 5   right?

darkbluechocobo · Answer

yes sorry i forgot to put the ^

cwrw238 · Answer

OK well the +1 in the bracket will move the whole graph of x^5 1 place to the left
then the negative outside the bracket will reflect it in the x axis
and finally the -5 will move the graph downwards 5 units

darkbluechocobo · Answer

Alright

cwrw238 · Answer

i'm trying to figure it out 
i'm not very good at these

got any ideas about what happens to the point (1,1)?

darkbluechocobo · Answer

basically base graph is x^5

darkbluechocobo · Answer

so i assume it has to be with the placement of that

cwrw238 · Answer

yes  now 1 move to the left will take (1,1)  to (0,1)  right  only the value of x will change

cwrw238 · Answer

agreed?

darkbluechocobo · Answer

yes

cwrw238 · Answer

ok now reflection in x axis will take the y value 1 to -1,  x will remain the same
so the point goes to (0,-1)

cwrw238 · Answer

then the -5 takes y value  to -6

so its (0,-6)

cwrw238 · Answer

its worth getting a copy of the main graph transformations
google it - its out there somewhere