Question

Prove the following (X+Y)(X'+Z) = XZ + X'Y

Answer 1

XX' +XZ + YX' + YZ = XZ + X'Y

Answer 2

Using the law X * X' = 0

Answer 3

XZ+YX' +YZ

Answer 4

Using consensus theorem to the following
XZ+X'Y+YZ = XZ + X'Y

Answer 5

Therefore They're logically equivalent

Answer 6

Prove (X+Y)(Y+Z)(X'+Z) = (X+Y)(X'+Z)

Answer 7

hmm Consensus theory proof...

Answer 8

ofcourse no one is on lol

Answer 9

just read.... truth tables.... funnn

Answer 10

So you help proving Prove (X+Y)(Y+Z)(X'+Z) = (X+Y)(X'+Z)
?

Answer 11

nah it's a truth table question

Answer 12

isn't this the theorem where you add A'A

Answer 13

@freckles .. however if you can give a few tips on how to go about doing a factor out question or SOP TO POS that'd be cool

Answer 14

@freckles

Answer 15

So you say this is about truth tables?

Answer 16

KLMN' + K'L'MN+MN'

KLMN' + MN' + K'L'MN

MN'(KL+1) + K'L'MN

MN' + K'L'MN