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OpenStudy (anonymous):
State how many imaginary and real zeros the function has. f(x) = x3 + 5x2 + x + 5 0 imaginary; 3 real 1 imaginary; 2 real 3 imaginary; 0 real 2 imaginary; 1 real
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OpenStudy (anonymous):
it cannot have one imaginary or 3 imaginary since they come in pairs so it has either 2 imaginary or none
OpenStudy (anonymous):
if you want to know if it has one real and two imaginary or three real, graph it
OpenStudy (anonymous):
http://www.wolframalpha.com/input/?i=+x3+%2B+5x2+%2B+x+%2B+5 looks like this is actually \[(x+5)(x^2+1)\] so one real, namely \(-5\) and two imaginary \(i,-i\)
OpenStudy (anonymous):
thank you @satellite73
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