Question

two questions attached:) Help?:) Pretty please

Answer 1

chain rule away for the first one

Answer 2

the derivative of sine is cosine
then the derivative of square root of something is one over two root something
the derivative of cosine is minus sine
the derivative of tangent is secant squared
the derivative of \(\pi x\) is \(\pi\)

Answer 3

it is really really long and drawn out
your math teacher must hate you

Answer 4

\[\cos\left(\sqrt{\cos(\tan(\pi x))}\right)\times ...\] is the first part

Answer 5

then
\[\frac{1}{2\sqrt{\cos(\tan(\pi x))}}\times ...\] is the second

Answer 6

then\[-\sin(\tan(\pi x))\times ...\]

Answer 7

math hates me in general lol!!!

Answer 8

then
\[\sec^2(\pi x)\times ...\]

Answer 9

you're the best!!!

Answer 10

finally \(\times \pi\)

Answer 11

it is going to be really hard to write this without making a mistake
pull the \(-\pi\) out front

Answer 12

thanks !

Answer 13

i'll write it and screenshot it to make sure its right:)

Answer 14

good luck!!

Answer 15

\[-\pi \cos\left(\sqrt{\cos(\tan(\pi x))}\right)\times \frac{1}{2\sqrt{\cos(\tan(\pi x))}}\times \sin(\tan(\pi x))\times\sec^2(\pi x)\] lol

Answer 16

OMG YOUR SO AWESOME!!!! THANK YOU!! THANK YOU THANK YOU!!!

Answer 17

*YOU'RE

Answer 18

it worked?

wowowow

Answer 19

yes it did!!!!:D

Answer 20

ok i guess we have to look at the second one then....

Answer 21

it worked:D LOOOKKK

Answer 22

lol sorry:/

Answer 23

that is ok second one is much easier

Answer 24

okay:) i seriously don't know how u did it!!! its awesome can't believe i got it right! i like tripled check i copied everything right before submitting it lol

Answer 25

it is chain rule repeated like 5 times
for the next one, you know the derivative?

Answer 26

again!!!?? & yes is it this

Answer 27

-8(x+1)/x^2(x-2)^2

Answer 28

i mean x-1 not x+1

Answer 29

i am don't think so

Answer 30

\[\frac{4}{(x^2-2x)^2}\] right?

Answer 31

agh its wrong;/?

Answer 32

that is the function, yes?

Answer 33

i got a (x-1) on the numerator

Answer 34

not sure what rule you are using
i would avoid the quotient rule for this one since the numerator is a constant

Answer 35

mmmmm i still need to practice more:(

Answer 36

the derivative of \(\frac{1}{x^2}\) is \(-\frac{2}{x^3}\) so the derivative of
\[\frac{4}{(x^2-2x)^2}\]is
\[-\frac{8(2x-2)}{(x^2-2x)^3}\]

Answer 37

or you could write it as
\[4(x^2-2x)^{-2}\] and use the power rule and the chain rule

Answer 38

then plug in 3 and see what you get

Answer 39

4/9

Answer 40

? same as the point

Answer 41

btw if my explanation above was not so clear, let me rewrite it like this
since the derivative of
\[\frac{1}{x^2}\] is
\[-\frac{2}{x^3}\] then by the chain rule the derivative of
\[\frac{1}{f^2(x)}\] is \[-\frac{2f'(x)}{f^3(x)}\]

Answer 42

seems unlikely they would be the same
let me check

Answer 43

no it was clear don't worry, i don't want to make you work a lot lol!!! Thank you i very much appreciate it!!

Answer 44

okay, maybe i did something wrong lol as usual

Answer 45

i think it is \(-\frac{32}{27}\) should i write it out?

Answer 46

\[f'(x)=-\frac{8(2x-2)}{(x^2-2x)^3}\]
\[f'(3)=-\frac{8\times 4}{3^3}\]

Answer 47

no i think i plugged them in wrong in my calculator lol

Answer 48

let me guess, you plugged it in to the original function

Answer 49

i see it:) thank you!

Answer 50

something like that lol -_-

Answer 51

calculator is not your friend here, it is easier to see the arithmetic without it

Answer 52

yea, i just didn't want one small mistake to ruin my whole answer the math homework system hates me lol, it seems to love you

Answer 53

thank for advice!!!

Answer 54

love that webassign
(right)
you get it right?

Answer 55

lol yes i do!!!!!!!!!!!!! hahaha

Answer 56

yay

Answer 57

oh wait hold on lol i haven;t submitted it!! i meant i got it that you love webasign

Answer 58

-32/27 is answer right? I'm about to submit it

Answer 59

its right

Answer 60

:)

Answer 61

that is what i get
i would be $32 that it is right

Answer 62

thank you!!:)

Answer 63

<3 :) yeayyyy!!!!

Answer 64

you're awesome!!!

Answer 65

yw
(invoice is in the mail)

Answer 66

(blush)

Answer 67

yeayyyy have an 80 from a 65 thanks to you!!

Answer 68

lol silly!

Answer 69

3 more to go
have fun!

Answer 70

i will!!! I'm getting the hang of it!!:D

Answer 71

post in a new thread if you need more help

Answer 72

i will thank you!!! i have till 12 to finish them so i'll try for now, i don't like making you guys do all my work lol