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Mathematics 9 Online
OpenStudy (anonymous):

i have certain questions on introduction to history of math

OpenStudy (anonymous):

OpenStudy (anonymous):

@ganeshie8 kindly

ganeshie8 (ganeshie8):

which question ?

OpenStudy (anonymous):

question 1 and 3 please

OpenStudy (anonymous):

sorry 1 and 4 please

ganeshie8 (ganeshie8):

lets see #4 first

OpenStudy (anonymous):

yea sure

ganeshie8 (ganeshie8):

\(\large \frac{1}{7} \uparrow \) and \(\large \frac{1}{9} \downarrow \) that doesn't tell us the net effect visully, so lets change both fractions to a common base so that comparison becomes easy

OpenStudy (anonymous):

ok cool..

OpenStudy (anonymous):

please proceed further

OpenStudy (anonymous):

sir is available ?

ganeshie8 (ganeshie8):

no man openstudy wont cooperate http://prntscr.com/4ph76e

ganeshie8 (ganeshie8):

the post button keeps hiding and the page never loads, its really frustrating

OpenStudy (anonymous):

ha... fine,,,, i have found a way to sort out question 1, but i need help for the above question and 5 too

OpenStudy (anonymous):

dont let me down kindly, thank you

ganeshie8 (ganeshie8):

\(\large \frac{1}{7} \uparrow \) and \(\large \frac{1}{9} \downarrow \) is same as \(\large \frac{9}{63} \uparrow \) and \(\large \frac{7}{63} \downarrow \) So it climbs 9/63 handbreadths and falls back 7/63 handbreads, the net effect is\(\large \frac{2}{63} \uparrow \), yes ?

ganeshie8 (ganeshie8):

Overall, the lion climbs UP 2/63 handbreadths each day

OpenStudy (anonymous):

yes i get what u say

ganeshie8 (ganeshie8):

and the pit is 50 handbreadth deep so divide 2/63 to get number of days the lion takes to reach the top

ganeshie8 (ganeshie8):

50 handbreadths to climb up 2/63 handbreadth per day So number of days it takes = 50/(2/63) = ?

OpenStudy (anonymous):

315/2=157.5

ganeshie8 (ganeshie8):

3150/2 = 1575

OpenStudy (anonymous):

sorry 3150/2

OpenStudy (anonymous):

thank you!!!

OpenStudy (anonymous):

question 5 please

ganeshie8 (ganeshie8):

You're given \[\large a_n = 2a_{n-1} - 12 ;~~a_4 = 9\]

ganeshie8 (ganeshie8):

You need to find \(\large a_0\)

ganeshie8 (ganeshie8):

familiar with recursive sequences ? if not, we can work it using another method

OpenStudy (anonymous):

no am not

OpenStudy (anonymous):

but u can teach me

OpenStudy (anonymous):

there ??

ganeshie8 (ganeshie8):

say he had "x" denari in the beginning

ganeshie8 (ganeshie8):

start : x Lucca : 2x-12 Florence : 2(2x-12) - 12 Pisa : 2[2(2x-12)-12] - 12

ganeshie8 (ganeshie8):

set the last expression equal to 9 and solve x

ganeshie8 (ganeshie8):

2[2(2x-12)-12] - 12 = 9 x = ?

OpenStudy (anonymous):

just a moment

OpenStudy (anonymous):

8x-72=9

OpenStudy (anonymous):

8x=81

ganeshie8 (ganeshie8):

doesn't look correct, check ur work again

OpenStudy (anonymous):

sorry i left a 12

OpenStudy (anonymous):

8x=93

OpenStudy (anonymous):

thats what i got. is it correct ?

OpenStudy (anonymous):

Thanks sir

ganeshie8 (ganeshie8):

looks good to me, check if it really satisfies the given situation by starting with 93/8 and carrying out the given sequence of steps

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