Question

The area of a rectangular lot is increased by 25 m^2 if it is longer by 10 m and narrower by 2.5 m, but when it is shorter by 10m and wider by 5m its area is reduced by 50m^2. Find the area and the dimensions of the lot.

Answer 1

How do you solve this?

Answer 2

(x+10) (y-2.5) = xy + 25
(x-10) (y+5) = xy - 50

solve and x = 20, y = 10

Answer 3

so area = 20 x 10 = 200

Answer 4

@sourwing how did you obtain the values 20 and 10?

Answer 5

When the two equations of @sourwing are expanded and then simplified, the result is the following two equations:
10y - 2.5x = 50 .........................(1)
-10y + 5x = 0 ...........................(2)
When equations (1) and (2) are added we get:
2.5x = 50 .........................(3)
The solution to equation (3) is: x = 20 m. Plugging this value of x into equation (1) gives
y = 10 m.

Answer 6

@kropot72 thanks for the explanation

Answer 7

You're welcome :)