Question

As a train accelerates away from a station, it reaches a speed of 4.5m/s in 4.8s . If the train's acceleration remains constant, what is its speed after an additional 7.0s has elapsed?

Answer 1

Hello @guiwuzhe456 !
Welcome to OpenStudy !

Answer 2

Do you the equations of motion ?

Answer 3

Using the equation
v=u+at
We cn frst find the acceleration of the train as

4.5=0+a*4.8
=> a= 4.5/4.8=0.937 m/s^2

Now again using the same equation we can find the final final velocity as

v=0+0.937*11.8

=> v= ?

Answer 4

v=11.0566