Question

(square root 48 + square root 27)2

Answer 1

\((a+b)^2 = a^2 + 2ab + b^2\)

Answer 2

\[\sqrt{48}\]= 6.92..... + \[\sqrt{27}\]= 5.196.....= 12.124... * 2 = 24.25.

Answer 3

\[
(\sqrt{48} + \sqrt{27})^2 = (\sqrt{48})^2 + 2(\sqrt{48})(\sqrt{27}) + (\sqrt{27})^2 = \\
48 + 2\sqrt{48*27} + 27 = 75 + 2\sqrt{16*3*3*9} = \\
75 + 2\sqrt{4^2*3^2*3^2} = 75 + 2 * 4 * 3 * 3 = 75 + 72 = 147\\
\]

Answer 4

sqet48 = 4sqrt3
sqer27 = 3sqrt3

assum it will get 7sqrt3

so 7sqrt3 squared is equal 49*3 = 147

hope this will help you