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What is the final digit in the number 2687^398? Hint: First compute 7^1, 7^2, 7^3, 7^4, 7^5,..., until you see a pattern. Why are the final digits of these numbers the same as the final digits of 2687^1, 2687^2, 2687^3....,?
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9 from the actual expansion of 2687^398 by Mathematica, a program capable of unlimted precision arithmetic. The expansion is attached.
Okay, in class though, one person said that you could do it based on a pattern with the different powers of 7, do you know anything about that?
@robtobey
use the given hint
consider last digits of powers of 7 : 7^1 : 7 7^2 : 9 7^3 : 3 7^4 : 1 7^5 : 7 7^6 : 9 7^7 : 3 ... see any pattern ?
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