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9a^2 * 5/36 <-fraction
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is it: \[9a^2*\frac{ 5 }{ 36 }?\]
yes
ok, what is your question?
how to calculate it
i mean solve the problem *
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are you trying to reduce to a simple term or solving for a?
multiply and simplify
@kl0723
there you go :) it shouldn't be that difficult
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how did you get 5 for the numerator?
@kl0723
@nicoleced ohh ok, notice that the numerator and the denominator are divisible by the number 9 (sorry I wrote 4) :( so you have simplify by extracting 9 from top and bottom
you now will have, \[\frac{ 45 = (5*9) }{ 36=(4*9) } \] in other words you simplify that 9 from both top and bottom, leaving you with the remaining \[\frac{ 5 }{ 4 }\]
the 9 on the top will cancel out with the 9 on the bottom :)
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yess, i get it now! thanks! :)
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