For what value of the constant c is the function f continuous on ( -infinity , infinity ) where f(x)={cx+3 if x \in (-infinity,8] {cx^2-3 if x \in (8,infinity)
Those "\in"s should be \[\in\]
The function is continuous if \[\lim_{x\to8^-}f(x)=\lim_{x\to8^+}f(x)\] and if \(f(8)=8c+3\). Use the limit equation to solve for \(c\).
That's what I tried doing...I got 8c+3, then 64c-3 for the other side. Set the two equations together and I got c=9.333. I put that in to my homework thing and it says I have the wrong answer.
I don't think your \(c\) is right.
\[\begin{align*} 8c+3&=64c-3\\ 56c&=6\\ c&=\frac{3}{28} \end{align*}\]
oh wow, I divided by the wrong side, like I had the c attached to 6. That was an idiot move. Lemme try 3/28. It worked. Thanks!
You're welcome!
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