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Mathematics 13 Online
OpenStudy (anonymous):

how do you solve this problem... For f(x)=-3x^2+2x+1, find f(4+h)-f(4)/h. Simplfy completely

OpenStudy (anonymous):

Substitute (4+h) and (4) into your function...

OpenStudy (anonymous):

like -3(4+h)-(4)+2(4+h)(4)+1?

OpenStudy (anonymous):

-3(4+h)+2(4+h)+1 - (-3(4)^2+2(4)+1) /h Do yu see what I did?

OpenStudy (anonymous):

yeah i think so.

OpenStudy (anonymous):

but you don't write the first as -3(4+h)^2+2(4+h)+1? and why did you subtract them?

OpenStudy (anonymous):

Yes I made and error on the first part. You subtract them because you orginal equation f(4+h)-f(4). Understand.

OpenStudy (anonymous):

oh i see now.

OpenStudy (anonymous):

Now you need to expand your equation.

OpenStudy (anonymous):

so i would distribute them?

OpenStudy (anonymous):

Yes..be very careful when doing this as you must always remember that you are subtracting the whole equation. That is why I always place it in brackets and show it above as. Fist part of the equation..- (-3(4)^2+2(4)+1)...

OpenStudy (anonymous):

ok am I on the right track? -3(16+8h+h^2)+8+2h+1

OpenStudy (anonymous):

Yes distribute the -3

OpenStudy (anonymous):

ok would it be.... -39-22h-3h^2

OpenStudy (anonymous):

-48-24h-3h^2..now do the other part

OpenStudy (anonymous):

but what do you do with the 8+2h+1?

OpenStudy (anonymous):

Oh..my bad you combined terms..you are correct..

OpenStudy (anonymous):

ha yeah. Ok so is this all i do for this part of the problem?

OpenStudy (anonymous):

Yes..but you have to subtract the other part then divide the whole thing by h.

OpenStudy (anonymous):

okay so the other part other the problem i got a -22 so....-39-22h-3h^2-(-22) It's gonna become a plus sign?

OpenStudy (anonymous):

Not -22 might check that again

OpenStudy (anonymous):

oh ok so it's -39?

OpenStudy (anonymous):

Yes and you are right it will become positive. So what do you end up with?

OpenStudy (anonymous):

-22h-3h^2/h

OpenStudy (anonymous):

Which simplifies to what?

OpenStudy (anonymous):

22-3h?

OpenStudy (anonymous):

-22-3h?

OpenStudy (anonymous):

Very good...This is the difference equation you will see it many times in pre calculus...Do it few times and it becomes easy...Great job..

OpenStudy (anonymous):

oh okay ha thanks. Now how do I check if thats the solution?

OpenStudy (anonymous):

You would have to do it a second tome and see if you get the same result

OpenStudy (anonymous):

What do you mean? Just redo the problem?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

there isnt another way? like plugging in what we got into the equation?

OpenStudy (anonymous):

Hold on

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

Nope no way to check the answer in that this is a formula with h as a variable. And it is called the "Difference Quotient"

OpenStudy (anonymous):

ha ok I hope my teacher accepts that. thanks for your help

OpenStudy (anonymous):

Anytime

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