how do you solve this problem... For f(x)=-3x^2+2x+1, find f(4+h)-f(4)/h. Simplfy completely
Substitute (4+h) and (4) into your function...
like -3(4+h)-(4)+2(4+h)(4)+1?
-3(4+h)+2(4+h)+1 - (-3(4)^2+2(4)+1) /h Do yu see what I did?
yeah i think so.
but you don't write the first as -3(4+h)^2+2(4+h)+1? and why did you subtract them?
Yes I made and error on the first part. You subtract them because you orginal equation f(4+h)-f(4). Understand.
oh i see now.
Now you need to expand your equation.
so i would distribute them?
Yes..be very careful when doing this as you must always remember that you are subtracting the whole equation. That is why I always place it in brackets and show it above as. Fist part of the equation..- (-3(4)^2+2(4)+1)...
ok am I on the right track? -3(16+8h+h^2)+8+2h+1
Yes distribute the -3
ok would it be.... -39-22h-3h^2
-48-24h-3h^2..now do the other part
but what do you do with the 8+2h+1?
Oh..my bad you combined terms..you are correct..
ha yeah. Ok so is this all i do for this part of the problem?
Yes..but you have to subtract the other part then divide the whole thing by h.
okay so the other part other the problem i got a -22 so....-39-22h-3h^2-(-22) It's gonna become a plus sign?
Not -22 might check that again
oh ok so it's -39?
Yes and you are right it will become positive. So what do you end up with?
-22h-3h^2/h
Which simplifies to what?
22-3h?
-22-3h?
Very good...This is the difference equation you will see it many times in pre calculus...Do it few times and it becomes easy...Great job..
oh okay ha thanks. Now how do I check if thats the solution?
You would have to do it a second tome and see if you get the same result
What do you mean? Just redo the problem?
Yes
there isnt another way? like plugging in what we got into the equation?
Hold on
ok
Nope no way to check the answer in that this is a formula with h as a variable. And it is called the "Difference Quotient"
ha ok I hope my teacher accepts that. thanks for your help
Anytime
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