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Mathematics 17 Online
OpenStudy (anonymous):

P(x)=(105x)-(1500+10x+0.2x^2) How many items need to be made to make a profit?

OpenStudy (anonymous):

So for you to make a profit P(x) has to be greater than what?

OpenStudy (anonymous):

105x? I thought it would could be set up equal to each other but I'm not sure how to solve it with the exponent. 105x=1500 +10x+.2x^2?

OpenStudy (kirbykirby):

To have a profit, \(P(x)>0\). If it's equal to 0 exactly, you are not making profit. If it's less than 0, you have too many costs to make any profit (you have a "negative" profit). So, you should solve that inequality, \(P(x)>0\)

OpenStudy (anonymous):

So to solve I would set it up this way: (105x)-(1500+10x+.2x^2)>0?

OpenStudy (kirbykirby):

yes

OpenStudy (anonymous):

How do you solve for the exponent? -.2x^2 +95x>1500

OpenStudy (kirbykirby):

I think a good way to approach this would be to recognize this as a quadratic equation. When you have an equality, you typically put everything to the left side, and let it = 0. ANd then you factor the quadratic, or solve using the quadratic formula. I'd approach it the same way but instead of an equality, you have an inequality. I would probably use the quadratic formula since the quadratic doesn't look easily factorable.

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