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Mathematics 14 Online
OpenStudy (anonymous):

Hi, can someone please help me on an algebra II problem? http://goo.gl/n41gRF this is what I got so far: a^2/a^2=1 4-4=0 I am left with two m's. The final answer is m but that confuses me. Why isn't it 2m?

ganeshie8 (ganeshie8):

thats a good try! but we can't break a fraction like that

ganeshie8 (ganeshie8):

we need to pull out GCF of numerator and see if something cancels out

OpenStudy (anonymous):

do I factor to do that?

ganeshie8 (ganeshie8):

Notice that the numerator has two terms : \(\large a^2m+4m\)

ganeshie8 (ganeshie8):

yes, whats the GCF of the terms ?

ganeshie8 (ganeshie8):

both terms have \(\large m\) in common right ? factor that out

OpenStudy (anonymous):

ohhh yea

ganeshie8 (ganeshie8):

you get \(\large a^2m+4m = m(a^2+4)\)

ganeshie8 (ganeshie8):

Now you can canccel \(\large a^2+4\) in the numerator and denominator and you will be left with just \(\large m\)

ganeshie8 (ganeshie8):

\[\large \dfrac{a^2m+4m}{a^2+4} = \dfrac{m(a^2+4)}{a^2+4} = m\]

OpenStudy (anonymous):

Thank you! that helped. I'm just learning this material so im a little shaky with it

ganeshie8 (ganeshie8):

remember this : you can only cancel after factoring, you canot cancel the individual terms...

OpenStudy (anonymous):

you;re amazing lol. I took notes on everything you typed

OpenStudy (anonymous):

ok thanks :)

ganeshie8 (ganeshie8):

no, you're amazing :) good luck with the practice!

OpenStudy (anonymous):

Aww thank you

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