Question

I need help simplifying this trig function..

Answer 1

\[\tan(\frac{ \pi }{ 2}-x)sinx\]

Answer 2

what is the difference identity for tan?

Answer 3

Reciprcol identity?

Answer 4

\[\frac{ 1 }{ \cot t }\]

Answer 5

way nevermind we can't use the difference identity here
tan(pi/2) doesn't exist
no i was talking about the difference not reciprocal

Answer 6

write tan in terms of sin and cos

Answer 7

\[\tan(u \pm v) = \frac{ \tan u \pm \tan v }{ 1\pm \tan u \tan v }\]

Answer 8

That's the difference identity right.

Answer 9

then use the difference identitys for sin and cos

Answer 10

then you will something cancel :)

Answer 11

co function identity is \[\tan(\frac{ \pi }{ 2 }-u)= \cot u\]

Answer 12

if you want you can use that as well

Answer 13

so then we'd have \[\cot x \sin x\]

Answer 14

write cot in terms of sin and cos

Answer 15

Then what? Quotient identity?

Answer 16

recall cot(x)=cos(x)/sin(x)

Answer 17

Mkay. So sin x would cancel out and we'd be left with cos x. right?(:

Answer 18

right

Answer 19

Ty freckles.

Answer 20

you did awesome by yourself
you decided to use the co-function identity

Answer 21

So if the function didn't have pi/2 in the beginning and it just had a real number like 3. Then i would have used the difference identity, right?