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OpenStudy (anonymous):
Element “X” has three isotopes X-234 (0.005% abundance, mass of 234.041 amu), X-235 (0.720% abundance, mass of 235.044 amu), and X-238 (99.275%, mass of 238.051 amu). What is the average atomic mass of element “X”?
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OpenStudy (anonymous):
M = (234.041x.005%) + (235.044x.72%) + (238.051x99.275%) = 238.029 (amu)
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