Find the perimeter of the shape below:

Question

lilcathyx · Answer

attachment

lilcathyx · Answer

12.4 units

 13.4 units

 15.1 units

 16.8 units


 i say 13.4 units

anonymous · Answer

use Pythagoras theorem

shinalcantara · Answer

you need to find the distance for each side..
let's start with EF
$$EF = \sqrt{(6-4)^{2} + (-1-2)^{2}}$$
EF =?

anonymous · Answer

i think a

lilcathyx · Answer

EF = Sq root of 13 = 3.6 
so EF= 3.6 ?

shinalcantara · Answer

next we'll have FG
$$FG = \sqrt{(4-3)^{2} + (2-(-1))^{2}}$$

anonymous · Answer

it's easy to use Pythagoras thm then this formula EF=sqrt(2^2 + 3^2)
similarly FG=sqrt(1^2+3^2)

shinalcantara · Answer

HG = 2 units since it doesn't have a change in vertical distance

shinalcantara · Answer

$$HE = \sqrt{(6-3)^{2} + (-1-(-3))^{2}}$$

shinalcantara · Answer

by the way i'm using the distance formula:
$$d = \sqrt{(x2-x1)^{2} + (y2 - y1)^{2}}$$

lilcathyx · Answer

I did the distance formula for all the sides. and i just noticed i did HE wrong i got "sq root of 18 which equals 4.2" and now i did it the way you wrote it and got " sq root of 13 which equals 3.6."

shinalcantara · Answer

after getting all the values.. Add them up and you'll have the value for the perimeter

lilcathyx · Answer

i got 12.4 :O Thank you !