Solve the system by the elimination method. Check your work.
3a + 5b - 7 = 0
a - 2b - 4 = 0

{(96/11, -5/11)}

{(34/11, -5/11)}

{(32/33, 5/11)}

Question

Solve the system by the elimination method. Check your work. 
3a + 5b - 7 = 0
a - 2b - 4 = 0



{(96/11, -5/11)}

{(34/11, -5/11)}

{(32/33, 5/11)}

anonymous · Answer

@kl0723 or & @perl can you help?

kl0723 · Answer

ok, your answer should of the form (x,y) that means one point for x and one for y or in this case (a,b)

kl0723 · Answer

you have two variables and must get rid of one of them... try by multyplying the second equations by -3 to make the a values cancel out :)

anonymous · Answer

I have no calculator or anything on me. That's why im asking for it :c

kl0723 · Answer

don't really need one :) $$3a + 5b -7 = 0$$
                                      $$a - 2b -4 = 0$$ whole equation times (3)

anonymous · Answer

youd have to multiple it by -3 not just 3

kl0723 · Answer

I meant (-3), so you will have now -3a +6b +12 = 0... this is your second equation :)

anonymous · Answer

multiply*

perl · Answer

3a + 5b - 7 = 0
 a - 2b - 4 = 0

Rewrite in the form ax +by = c 

3a + 5b = 7
a - 2b = 4

perl · Answer

ok so far?

perl · Answer

i added 7 to both sides of the first equation, and added 4 to both sides of the second equation

anonymous · Answer

I just guessed on my work its ok.

kl0723 · Answer

don't guess! we're trying to make sure you understand how to get to your answer, if we just give you an answer we're not helping at all

anonymous · Answer

it was just that question! everything else is graphing.

perl · Answer

now multiply second equation by -3