Ask your own question, for FREE!
Mathematics 12 Online
OpenStudy (darkbluechocobo):

Two objects with different masses interact, characterize the forces

OpenStudy (darkbluechocobo):

They must be different They might be different always equal and opposite always the same

OpenStudy (darkbluechocobo):

would this be b? because you dont know the amount of force of them but you know they have different masses

OpenStudy (darkbluechocobo):

it just depends on which one has the bigger mass

geerky42 (geerky42):

Yeah, I agree. Netwon's Second Law is \(F=ma\) Therefore forces are different since masses are different.

OpenStudy (darkbluechocobo):

but its not a must right?

OpenStudy (darkbluechocobo):

im like debating on a and b :/

geerky42 (geerky42):

oh now you mention it, I believe it's B since acceleration can be different too.

geerky42 (geerky42):

different masses and acceleration can be equal, like \(6\cdot6 = 9\cdot4\)

OpenStudy (darkbluechocobo):

yes thats actually the next question about the accelerations of the 2

OpenStudy (darkbluechocobo):

would the answer be the same about the acceleration saying you dont know the mass ?

ganeshie8 (ganeshie8):

im inclining more toward c, the forces need to be equal and opposite

geerky42 (geerky42):

What do you think? @ganeshie8 I am not fully confident though :)

OpenStudy (darkbluechocobo):

so ganeshie like a baseball bat and a ball?

ganeshie8 (ganeshie8):

yeah but wait, i don't think that should be the case always

geerky42 (geerky42):

yeah, something like this is why I am not confident with my answer.

geerky42 (geerky42):

lol

ganeshie8 (ganeshie8):

the objects can travel in the same direction after collision also : |dw:1411595815583:dw|

geerky42 (geerky42):

LOL! I googled "Two objects with different masses interact, characterize the forces" and first link leads to here

ganeshie8 (ganeshie8):

google might be making fun of us haha!

OpenStudy (darkbluechocobo):

ahaha :p but its like we dont know the force or the acceleration so what is the possibility of it being different?

geerky42 (geerky42):

We shouldn't concern about the possible for certain things to happen. we just need to consider cases.

OpenStudy (darkbluechocobo):

ah

OpenStudy (darkbluechocobo):

@geerky42 so i found this Rearranging gives the equation: mA ∕ mB = aB ∕ aA From this equation it appears that the accelerations are equal only when the two masses are equal. Otherwise, for the case where the masses are unequal, there is also a difference in the accelerations.

geerky42 (geerky42):

yeah, that makes sense. However difference in accelerations and masses could wind up to be equal F = 4kg * 9m/s^2 = 36 N F = 6kg * 6m/s^2 = 36 N So even if masses are different, force could be same. hence B instead of A.

geerky42 (geerky42):

Or at least what I believe.

OpenStudy (darkbluechocobo):

I was thinking the same thing you were thinking sos i agree with you

OpenStudy (darkbluechocobo):

but what could you say about acceleration

OpenStudy (darkbluechocobo):

they might be different they must be different always the same or unkown

OpenStudy (darkbluechocobo):

unknown*

OpenStudy (darkbluechocobo):

would it be the same as the force question ?

geerky42 (geerky42):

I think so?

geerky42 (geerky42):

Wait, are forces same?

OpenStudy (darkbluechocobo):

well its the same question just with characterize the acceleration

OpenStudy (darkbluechocobo):

so id say so

OpenStudy (darkbluechocobo):

well then id say that would be unknown then aha

geerky42 (geerky42):

I just remembered about formula mA ∕ mB = aB ∕ aA

OpenStudy (darkbluechocobo):

yes that means if it is equal does it not?

geerky42 (geerky42):

So \(m_Aa_A = m_Ba_B\) So according to this formula, if masses are different, then accelerations MUST be different.

geerky42 (geerky42):

Acceleration HAVE to be different, so \((ma)_A\) can be equal to \((ma)_B\)

OpenStudy (darkbluechocobo):

Alrights so if mass different acceleration has to be different that makes sense

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!