Question

show that f is the function defined by f(x) = mx+b where m is not equal to 0, then the inverse function f^-1 is defined by the formula f^-1(y) =(1/m)y - (b/m)

Answer 1

solve
\[y=mx+b\] for \(x\)

Answer 2

y-b/m = x

Answer 3

right? @satellite73

Answer 4

then (y-b)/m = (1/m)y-(b/m)

Answer 5

then (y-b)/m = (y/m)-(b/m) which is (y-b)/m

Answer 6

thanks!

Answer 7

I don't buy it.

You haven't shown that the range of f(x) is the domain of f^-1 or the domain of f(x) is the range of f^-1(y)

In other words, you need to show that f(f^-1(y)) = y and that f^-1(f(x)) =x