Algebra
11 Online
OpenStudy (anonymous):
the graph of f(x) = 2^(x + 4) shifts five units to the right when it is replaced with the graph of f(x) = 2^(x - k). What is the value of k?
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OpenStudy (anonymous):
@jim_thompson5910 can you help me with this one too? Its -5 right?
jimthompson5910 (jim_thompson5910):
hint: to shift f(x) to the right 5 units, you replace x with x-5
so we need to find f(x-5)
OpenStudy (anonymous):
Okay, \[f(x - 5) = 2^{ -5 +4}\]?
jimthompson5910 (jim_thompson5910):
where did x go on the right side?
OpenStudy (anonymous):
Wait a second.. I replaced it with -5, and I shouldn't have.
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OpenStudy (anonymous):
\[f(x -5) = 2^{x -5 + 4}\]
jimthompson5910 (jim_thompson5910):
better
jimthompson5910 (jim_thompson5910):
now simplify
OpenStudy (anonymous):
\[-5+4 = -1\]\[f(x - 5) = 2^{x -1}\]
and I'm drawing a blank here.
OpenStudy (anonymous):
could I add 5 on both sides?
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jimthompson5910 (jim_thompson5910):
compare 2^(x-1) to 2^(x-k)
OpenStudy (anonymous):
Does that mean that the answer is 1?
jimthompson5910 (jim_thompson5910):
it does
jimthompson5910 (jim_thompson5910):
k = 1
OpenStudy (anonymous):
My initial answer moved 9 units, not 5.
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jimthompson5910 (jim_thompson5910):
yeah a graph confirms it
with k = 5, you move over 9 units to the right
OpenStudy (anonymous):
Thank you, I really appreciate your help. You're like the only person I understand when I'm on here.
jimthompson5910 (jim_thompson5910):
you're welcome