Question

POS TO SOP: (K'+M'+N)(K'+M)(L+M'+N')(K'+L+M)(M+N)

Answer 1

@nincompoop

Answer 2

familiar with kmap ?

Answer 3

As a start : take the negation and simplify using demorgan law

Answer 4

that would be like donkey work, we won't learn anything - waste of time

Answer 5

well it's going to be on the exam so...

Answer 6

anyways first you can get rid of a whole sum by just X(X+Y) = X with (K'+M)

Answer 7

which is what i did first

Answer 8

if you're allowed to use laws/theorems, why not use demorgan laws ?

Answer 9

because it says factor out.... if it said just simplify i'm assuming it'd be fair game

Answer 10

so in other words i have to factor backwards

Answer 11

what do you get for kmap

Answer 12

then its straigtforward, go ahead and factor out
whats stopping you ?

Answer 13

Factoring out would create way too many terms it needs to be simplified first

Answer 14

somewhere in my work there is a sligh error

Answer 15

unless what i have is logically equivalent but i doubt it

Answer 16

laughing out loud I wouldn't know what you have

Answer 17

this is something I would need to look and learn @Outkast3r09 at this point this is out of my league

Answer 18

well i have from just that simplification you get


(K'+M'+N)(K'+M)(L+M'+N')(M+N)

Answer 19

now the first part is simply (X+Y)(X+Z) = X+YZ

(K'+(M'+N)(M)) = (K'+0+NM)

Answer 20

(K'+NM)(L+M'+N')(M+N)

(K'+NM)(M+N)= K'M+K'N+NMM+NNM = K'M+K'N+NM+NM = K'M+K'N+NM

(K'M+K'N+NM)(L+M'+N')

K'ML+K'MM'+K'MN'+K'NL+K'NM'+K'NN'+NML+NMM'+NMN'


K'ML+K'MN'+K'NL+K'NM'+NML

Answer 21

K'(ML+MN'+NL+NM')+NML

Answer 22

I don't get the first simplification you did

Answer 23

K'(ML+M'N+NL+MN')+NML (consensus gets rid of NL

K'ML+K'M'N+K'MN'+NML

Answer 24

oh okay I see it now

Answer 25

which is correct other than the term K'ML

Answer 26

you can get rid of K'ML too

Answer 27

combine it with last two terms

Answer 28

how so

Answer 29

K'ML+K'M'N+K'MN'+NML

K'ML(N+N') + K'M'N+K'MN'+NML

Answer 30

Notice that : K'MLN + NML = NML(K'+1) = NML

Answer 31

combine the other term similarly

Answer 32

see that's why... our teacher never went over with using (N+N') as a substitute

Answer 33

K'MLN' + K'M'N+K'MN'+NML

K'MN'L + K'MN' = K'MN'

Answer 34

is there a procedural way to know when you'll need to add a term

Answer 35

or is it just by using it a lot

Answer 36

not sure if there is a procedural way but this trick wont be useful when you have logic with million gates to simplify