Question

To open these doors, you must match the number and type of solutions for the following two functions in standard form.
f(x) = x2 + 6x – 16
g(x) = x2 +6x + 1
Match the following descriptions of the solutions to each of the functions above.
Hint: they each have their own match.

Two real irrationals solutions
Two real rationals solutions

Answer 1

Help me @mathmale @iGreen

Answer 2

SO I was thinking that F(x) has two real rationals solutions and G(x) has two real irrational solutions

Answer 3

Strictly speaking, f(x) = x2 + 6x - 16 and g(x) = x2 +6x + 1 don't have solutions; it's not until you set each one equal to zero that the possibility of finding solutions arises.

So:
Find the solutions of f(x) = x2 + 6x - 16=0 and of g(x) = x2 +6x + 1=0.

Answer 4

By the way, for clarity, please type "the square of x" as x^2, or as \[x^2\or write it by hand:

Answer 5

\[x^2\]

Answer 6

Im not sure how to solve @mathmale

Answer 7

Im having a really hard time with this assigment and its the last one i need to do to finish :(

Answer 8

Just what is it about the assignment that is hard for you? Put that into words, please.

Answer 9

The solving quadricts and all of that stuff:

I would give it a try though: Is it like this

f(x) = x2 + 6x – 16
x1= 2
x2=-3
for g(x) = x2 +6x + 1
x1=
−3+22√

x2=
−3−22√

Answer 10

Its -3-2 square root 2

Answer 11

Do you mean the following?