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Mathematics 4 Online
OpenStudy (anonymous):

Write -2x^3+6x^2+2x-6 in factored form

OpenStudy (liamschumm):

Ok, so we need to factor something out of it.

OpenStudy (liamschumm):

We can factor x out.

OpenStudy (liamschumm):

Hint: x^2 + 3x can be factored as x(x+3).

OpenStudy (anonymous):

i bet this is the dreaded "factor by grouping" right?

Elsa213 (elsa213):

\(\frak\Huge\rlap{\color{Magenta}{^*\star^\heartsuit~Welcome~To~Openstudy}}{\color{Orchid}{\:~~~~~~~~~~Welcome~To~Openstudy^*\star^\heartsuit}}\)

OpenStudy (anonymous):

gone latex crazy i see

Elsa213 (elsa213):

If you need any hep just tag me c: Also before you continue.... Please take some time to read The_Code_Of_Conduct: openstudy.com/code-of-conduct

Elsa213 (elsa213):

http://openstudy.com/code-of-conduct *

Elsa213 (elsa213):

please don't take it away from me satellite ;-;

OpenStudy (anonymous):

\[-2x^3+6x^2+2x-6 \] \[-2x^2(x-3)+2(x-3)\] is a start

OpenStudy (anonymous):

common factor is \(x-3\) so you get \[(-2x^2+2)(x-3)\]

OpenStudy (anonymous):

or if you prefer \[-2(x^2-1)(x-3)\]

OpenStudy (anonymous):

then factor the difference of two squares and end up with \[-2(x+1)(x-1)(x-3)\]

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