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OpenStudy (anonymous):
Write -2x^3+6x^2+2x-6 in factored form
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OpenStudy (liamschumm):
Ok, so we need to factor something out of it.
OpenStudy (liamschumm):
We can factor x out.
OpenStudy (liamschumm):
Hint:
x^2 + 3x can be factored as x(x+3).
OpenStudy (anonymous):
i bet this is the dreaded "factor by grouping" right?
Elsa213 (elsa213):
\(\frak\Huge\rlap{\color{Magenta}{^*\star^\heartsuit~Welcome~To~Openstudy}}{\color{Orchid}{\:~~~~~~~~~~Welcome~To~Openstudy^*\star^\heartsuit}}\)
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OpenStudy (anonymous):
gone latex crazy i see
Elsa213 (elsa213):
If you need any hep just tag me c:
Also before you continue.... Please take some time to read The_Code_Of_Conduct: openstudy.com/code-of-conduct
Elsa213 (elsa213):
please don't take it away from me satellite ;-;
OpenStudy (anonymous):
\[-2x^3+6x^2+2x-6 \]
\[-2x^2(x-3)+2(x-3)\] is a start
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OpenStudy (anonymous):
common factor is \(x-3\) so you get
\[(-2x^2+2)(x-3)\]
OpenStudy (anonymous):
or if you prefer
\[-2(x^2-1)(x-3)\]
OpenStudy (anonymous):
then factor the difference of two squares and end up with
\[-2(x+1)(x-1)(x-3)\]
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