Question

Help

Answer 1

The sum of an infinitely many terms of a GP is 3 times the sum of even terms.. The common ratio of the GP is

Answer 2

I am getting 2 as the answer

Answer 3

@gorv

Answer 4

lets the gp
a ar ar^2 ar^3 ar^4............
sum of infinite series=a/(1-r)
even term
ar ar^3 ar^5................ it will also be infinite
so sum = ar/(1-r^2)

Answer 5

yes

Answer 6

i did the same thing

Answer 7

\[\frac{ a }{ 1-r }=3*\frac{ ar }{ 1-r^{2} }\]

Answer 8

yes

Answer 9

then
r^2 -3r +2 = 0

Answer 10

\[\frac{ a }{ 1-r }=3*\frac{ ar }{ (1+r)(1-r) }\]

Answer 11

r=1 or r=2

Answer 12

1-r will get cancel from both side

Answer 13

and a also get cancelled

Answer 14

so
1=3r/(1+r)
1+r=3r
1=2r
r=1/2

Answer 15

why my method won't work

Answer 16

@gorv

Answer 17

can u sjow me what u did???

Answer 18

yes