Question

A spring has a natural length of 30 cm. If a 24-N force is required to keep it stretched to a length of 42 cm, how much work W is required to stretch it from 30 cm to 36 cm? (Round your answer to two decimal places.)

Answer 1

Work=force*distance

Answer 2

i need to find an equation for right?

Answer 3

*work

Answer 4

is that 24 N or 24 minus N?

Answer 5

24 newtons

Answer 6

ok. i just see a minus there. had to clarify

Answer 7

so any ideas

Answer 8

I'm actually supposed to find an equation for work and put it into an integral from 30 to 36 cm i just dont know how to start

Answer 9

@kirbykirby

Answer 10

F = k * x
24 N force to stretch it by (42-30 = 12) cm.
k = F / x = 24/12 = 2 N / cm

W = Force * Distance
dW = kx * dx

\[
W = \int_{x_1}^{x_2}kxdx = \int_{30}^{36}2xdx = ?
\]

Answer 11

396?

Answer 12

Yes, but you may have to convert units so that he answer is is Newton-meters instead of 396 Newton-centimeters.

Answer 13

it needs to be in Jouls

Answer 14

Yes, 396 Newton-Centimeters or 3.96 Newton-Meters = 3.96 Joules.

Answer 15

ok great