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Vertex of y=|4x-1|
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The vertex form of the absolute function is \(y=a|x-h|+k\), where the vertex is \((h, k)\). So you can transform what you have into the given form: \(|4x-1|\\= \left|4\left(x-\dfrac{1}{4}\right) \right|\\ =4\left|x-\dfrac{1}{4} \right|\) So you have that the vertex is \(\left( \frac{1}{4},0\right)\)
Hint: the x-coordinate of the vertex can be found by setting the quantity inside the absolute value operators equal to zero and solving for x. kirbykirby's approach is a very good one. My method will also give you x = 1/4.
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