Question

http://goo.gl/tLtisB i got a+3/5(a+3)^2 is it right?

Answer 1

\[
\frac{(a+3)^2}{(a-3)} \div \frac{5}{(a^2-9)} =
\frac{(a+3)^2}{(a-3)} \times \frac{(a^2-9)}{5} =
\frac{(a+3)^2}{(a-3)} \times \frac{((a+3)(a-3))}{5} = \\
\frac{(a+3)^3}{5}
\]

Answer 2

\(a^2-9 = a^2 - 3^2 = (a+3)(a-3)\)

Answer 3

where did u get the exponent 3?

Answer 4

\(\large (a+3)^2 \times (a+3) = (a+3)^3\)

Answer 5

ohhh...right. thank you very much. could you help me with another one? its rly complicated

Answer 6

go ahead.

Answer 7

http://goo.gl/ivbQal alright thanks

Answer 8

\[\large
\frac{xy+xz}{xz-z^2} \times \frac{xy-yz}{xz+yz} \div \frac{y^2+yz}{x^2+xy} = \\ \large
\frac{x(y+z)}{z(x-z)} \times \frac{y(x-z)}{z(x+y)} \times \frac{x(x+y)}{y(y+z)} = ?
\]Can you simplify now?

Answer 9

is it x^2 y /z^2y ?

Answer 10

Almost there. You can simplify further.

Answer 11

do i cancel the y's? to make it x^2/z^2

Answer 12

Yes!

Answer 13

yaaaaaayyyyy thanks that helped

Answer 14

You are welcome.

Answer 15

:D