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and my a and b are 0 and 2 and im stuck..
So you're looking for the volume of this as it's revolved about x = 2? Is there a specific method you must use?
yes yes
Alright, so you're using shell method then. Right, so we need a height and a radius. Well, the height is determined by the function itself, so h = x^3/4. The radius is found by essentially doing right minus left. The right is simply our axis of revolution, 2. The left is the distance from the y-axis to the graph, defined by x. So the radius is simply 2-x. |dw:1411719057073:dw| This gives us the integral \[2 \pi \int\limits_{0}^{2}(2-x)(\frac{ x^{3} }{ 4 })dx\]
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