Question

A rocket starts from rest and moves upward from the surface of the earth. For the first 10s of its motion, the vertical acceleration of the rocket is given by ay=(3.00m/s3)t, where the +y-direction is upward.

Answer 1

Equations:
D=Do + VoT + .5aT^2
V=Vo +aT

Height of the rocket will be
D= .5*3*10^2
150 meters after 10 seconds.

To calculate the speed
200 = .5*3*T^2
200/(.5*3)=T^2
sqrt(200/(.5*3))=T
T=11.54
V= 0 +3*11.54
34.641 m/s

Answer 2

Try that^