How many liters of methane gas (CH4) need to be combusted to produce 12.4 liters of water vapor, if all measurements are taken at the same temperature and pressure?

CH4 (g) + 2 O2 (g) -- CO2 (g) + 2 H2O (g)

Question

How many liters of methane gas (CH4) need to be combusted to produce 12.4 liters of water vapor, if all measurements are taken at the same temperature and pressure?

CH4 (g) + 2 O2 (g) --> CO2 (g) + 2 H2O (g)

anonymous · Answer

As you can see, we will need 1 CH4 to produce 12.4L water vapor.
Next, because all measurements are taken at the same temperature and pressure, the ratio of volume between CH4 and H2O will be equal to the ratio between the reaction molecules.

anonymous · Answer

@tinybookworm how can I calculate the ratio of volume between CH4 and H2O?

anonymous · Answer

It is right in the reaction. 1 CH4 --> 2 H2O

anonymous · Answer

So to produce 2L of H2O, you will have to use 1L of CH4.

anonymous · Answer

@tinybookworm so the answer is 12.4/2 = 6.2L (as it's proportional)?

anonymous · Answer

Correct.

anonymous · Answer

Thank you!

anonymous · Answer

I'm very happy to help.