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Mathematics 13 Online
OpenStudy (anonymous):

Please help! Will give medal!

OpenStudy (anonymous):

OpenStudy (anonymous):

Did you finish this?

OpenStudy (anonymous):

no :/

OpenStudy (anonymous):

Is ADE and AOC similar?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Then what do you think about the ratios AE/AC and AD/AO?

OpenStudy (anonymous):

do would be 25

OpenStudy (anonymous):

right?

OpenStudy (anonymous):

No. Actually,\[\frac{ AE }{ AC }=\frac{ AD }{ AO }\rightarrow AO=\frac{ AC \times AD }{ AE }=\frac{ 40 \times 12 }{ 15 }=32\]Therefore, DO = AO - AD

OpenStudy (anonymous):

so how would i respond to this

OpenStudy (anonymous):

i need to call my teacher and give her the answer, what would i tell her when he asks me about do and of

OpenStudy (anonymous):

do is 32

OpenStudy (anonymous):

Nope. DO = AO - AD We know that AO = 32 and AD =12, then DO = 32 - 12 = 20

OpenStudy (anonymous):

oh okay :)

OpenStudy (anonymous):

and OF?

OpenStudy (anonymous):

Sorry, I am thinking. Thank you for you patience.

OpenStudy (anonymous):

take your time :)

OpenStudy (anonymous):

Are OD and EF parallel?

OpenStudy (anonymous):

yupp

OpenStudy (anonymous):

Then DE = OF

OpenStudy (anonymous):

how would we find DE?

OpenStudy (anonymous):

You might call DE x. Then\[\frac{ AE }{ AC }=\frac{ DE }{ OC }\rightarrow \frac{ 15 }{ 40 }=\frac{ x }{ x+30 }\]You can now solve for x. The final answer is x = DE = OF

OpenStudy (anonymous):

If you get 18, then you are right.

OpenStudy (anonymous):

DO = 20 and OF = 18

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

wow thank you so much :-)

OpenStudy (anonymous):

You are very welcome

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