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Mathematics 7 Online
OpenStudy (anonymous):

Find an equation of the tangent line to the curve at the given point.

OpenStudy (anonymous):

\[y= \sqrt{x} (9,3)\]

hartnn (hartnn):

find the derivative first! know how to ?

OpenStudy (anonymous):

f(x)-f(a)/x-a

hartnn (hartnn):

derivative of y at point 9,3 will give you slope of tangent at that point

OpenStudy (anonymous):

I came up with \[-\frac{ 1}{ 2 }\]

OpenStudy (anonymous):

but that's the wrong answer

hartnn (hartnn):

you mean the slope as -1/2 ?

OpenStudy (anonymous):

i mean like y= \[-\frac{ 1 }{ 2 }\]

hartnn (hartnn):

ofcourse thats not correct...the slope isn't 0 have u solved a similar question before ?

OpenStudy (anonymous):

no

hartnn (hartnn):

ok, so you need to use the definition of derivative, right ? "f(x)-f(a)/x-a"

OpenStudy (anonymous):

yes thats what i should use but i don't know where to put what

hartnn (hartnn):

|dw:1411783189182:dw| you can solve limits question ?

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