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Could someone please help me with this question. The points A (-2, -1, z) B (2, 4, 3) and C (10, y, -1) are collinear. Find the values of y and z.
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I've got a neater way to do this, if you allow. If ABC are collinear, then the area of \(\triangle ABC\) is zero.
Do you know what the formula of the area of a triangle is given three points?
Otherwise, just try vectors, which I think @ganeshie8 is proficient in.
that area method works too, vectors method is also nice
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ah alright thx
AB = (4, 5, 3-z) BC = (8, y-4, -4) for AB and BC to be in same direction, the components must be proportional : \[\large \dfrac{4}{8} = \dfrac{5}{y-4} = \dfrac{3-z}{-4}\] solve y,z
let me know if that not clear enough
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