Question

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Answer 1

First, examine this sequence carefully and determine whether it's an arithmetic or a geometric sequence.

Answer 2

tn= a +(n-1)d
a= 2

Answer 3

Starting with -6, -4, -2, 0, ..., figure out how one gets from the first term to the second, from the second to the third, and so on. Yes: it's an arithmetic sequence. So, what do we do to that first term, -6, to obtain that second term, -4?

Answer 4

it is an AP
nth term
=a+(n-1)*d

Answer 5

where a is first term =-6
n is number ofterm tobe found =30
d= the amount added in each term=2

Answer 6

Cool. First term is -6 and we add nothing / add zero to obtain it.
Second term is -4, obtained by adding 1 times 2 to -6.

Third term? can you type an explanation?

Answer 7

gorv's approach is a good one too. the formula he/she is using is L=A+(N-1)D.

Answer 8

yeah

Answer 9

that's right. But we don't actually have to write out all of those terms and then count them to find n.

Answer 10

@mathmale u plzz plzzz xplain what u r xplaining

Answer 11

so that he /she can get a clear view

Answer 12

Cool. First term is -6 and we add nothing / add zero to obtain it: -6+(0)2
Second term is -4, obtained by adding 1 times 2 to -6. -6+(1)2

Third term? can you type an explanation? -6+(2)2

nth term?

Answer 13

Again, you could certainly keep adding 2 to each new term to get the next one. But all you have to do is to calculate -6+(30-1)*2. gorv is correct in using that (n-1) factor.

Answer 14

First term: n=1: -6+(1-1)*2=-6,
and so on.

Answer 15

Of course. Kudos to gorv also.