I'm think it's b is it? Let u = <-4, -3>. Find the unit vector in the direction of u, and write your answer in component form. <1, 1>
\(Unit~Vector = \dfrac{\mathbf u}{||~\mathbf u~||}\)
So how do I find the denominator?
\(||~\mathbf u~||\) is magnitude of \(\mathbf u\), So you basically use pythagorean theorem to find it. |dw:1411837314108:dw| \[||~\mathbf u~|| = \sqrt{(-4)^2+(-3)^2}\] Does that make sense?
Umm let me try to solve it
So 5i
Or would the denominator be 25 and not five @geerky42
\(=\sqrt{(-4)^2+(-3)^2}\\~\\=\sqrt{16+9} \\~\\=\sqrt{25}\\~\\=5\) So denominator would be 5.
So you have unit vector = \(\dfrac{\mathbf u}{5}\)
Oh so if you sqaure a number it becomes positive
Yes, squaring negative number will get you positive number.
Always.
Oh okay thanks :)
Welcome! You can handle the rest on your own?
Umm I believe so but I have another question that's a tad different Two forces with magnitudes of 100 and 50 pounds act on an object at angles of 50° and 160° respectively. Find the direction and magnitude of the resultant force. Round to two decimal places in all intermediate steps and in your final answer.
Two forces with magnitudes of 100 and 50 pounds act on an object at angles of 50° and 160° respectively. Find the direction and magnitude of the resultant force. Round to two decimal places in all intermediate steps and in your final answer.
Pounds act on an object at angles of 50° and 160° respectively.
Degree in place of all those boxes
@geerky42
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