Question

New Problem to be posted in picture
(Picture of my work so far)

Answer 1

anyone have any ideas?

Answer 2

f(1) =e, not =1 because e^1 =e

Answer 3

yeah i know its actually \[f(1) = \frac{ e ^{(1+h)}-e }{ h }\] i was just inputting my nunmbers, i just knew that that symplified to that.

Answer 4

f(1) =e, f(3) =e^3, so the rate is (e^3 -e )/(3-1)
\[\dfrac{e^3 -e^1}{3-1}\]

Answer 5

oh wow so i dont even have to use the "rate of change" formula?

Answer 6

I think so

Answer 7

alright well ill have to try and get that confirmed but ill go with that for now, ill move to next one and just write a note. thanks!