According to the Chebyshev rule, at least 96% of these funds are expected to have one year total returns between what two amounts?
what is your mean and std dev?
.96 = (1 - 1/k^2) solve for k to get the number of std. devs. then you need to be with that many std. devs of the mean so you'll have to convert.
The mean is 7.30 and the sd is 3.50 I would like someone to break it down for me mathematically
i did... do you understand chebyshevs inequality and what it means?
i do not :(
ok so, i calculated the percentage of the funds are expected to be within a +/-6 standard deviation of the meant to be 97.22% Then it asks me - at least 93.75% of these funds are expected to have one year total returns between what two amounts? How do i calculate that, please?
what chebyshev's theorem says is that no matter what the distribution of you data is, there is at least (1-1/k^2)% of the data within k standard deviations of the mean. so, let's say you have a mean of 7.30 and a standard deviation of 3.50, just like your problem. so how much of the data must be within 2 standard deviations? well, we use chebyshev's to calculate: \[1-\frac{ 1 }{ 2^2 }=1-\frac{ 1 }{ 4 }= \frac{ 3 }{ 4 }=75%\] we can use it in reverse too! say we want to know how many deviations are needed to contain 96% of our data (just like your problem). then we set up and solve for k: \[96\%=.96=1-\frac{ 1 }{ k^2 } \Rightarrow \frac{ 1 }{ k^2 }=.04 \Rightarrow k^2 = 25 \Rightarrow k = 5\] how are you up to here?
and that should be 75%
the 75 should be 75%
so now that you know how many standard deviations, you just need to figure out what that is in terms of the data... mean + 5 std. devs => 7.30 +5*3.50 = ? (upper limit) mean - 5 std. devs => 7.30 -5*3.50 = ? (lower limit)
So upper limit is 43.05 and lower is 8.05?
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