Find two vectors where the sum of their angles is equal to the angle of their vector sum
@zepdrix @iambatman
Is it a trick question?? xD
I have been stuck on this question for an insane amount of time
Oh and the question specifies that they are nonzero vectors
v = ai + bj u = ci + dj u+v = (a+c)i + (b+d)j angle of v w/ respect to x-axis: v.i = |v||i|cos(o1) a = sqrt(a^2 + b^2) * cos(o1) o1 = acos(a/sqrt(a^2 + b^2)) angle of u w/ respect to x-axix: u.i = |u||i|cos(o2) c = sqrt(c^2 + d^2) * cos(o2) o2 = acos(c/sqrt(c^2 + d^2)) angle of u+v w/ respect to x-axis: (u+v).i = |u+v||i|cos(o3) a+c = sqrt((a+c)^2 + (b+d)^2) * cos(o3) o3 = acos((a+c)/sqrt((a+c)^2 + (b+d)^2)) o1 + o2 = o3 acos(a/sqrt(a^2 + b^2)) + acos(c/sqrt(c^2 + d^2)) = acos((a+c)/sqrt((a+c)^2 + (b+d)^2)) The expression above must be satisfied in order to find two vectors that attend the requirements. Note that if u and v are linear combinations of each other, the resultant sum will have the same angle. Example: u = 1i + 2j and v = 5i + 10j u + v = 6i + 12j
Holy cow
Umm ok
I have never seen anything remotely like that in my entire life
hahahah maybe there is a simpler way to solve this but for now that is the only method i found
Ok, well thanks anyways. If you know ANYBODY that could help, I would very much appreciate it!
@ganeshie8
@jim_thompson5910
the only time I think that happens is when you have one vector reflected over the x axis
|dw:1411863588180:dw|
say we initially have this vector |dw:1411863606737:dw|
I have been stuck on this question for so long
and say the angle from the x axis to the vector is 30 degrees |dw:1411863632083:dw|
ok
if you reflect it over the x axis, you get |dw:1411863651570:dw|
Use magnitude too. I think thats what they want in the question
the angles add to 30 + (-30) = 0 degrees
*Please use magnitude as well :)
The issue is that they want me to use vector addition
They want the angle of a+the angle of b to equal the angle of r
the resultant vector is this |dw:1411863711762:dw|
so we can see that vector z has an angle of 0 degrees
Oh, that makes sense!! Thanks so much!!!
np
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