Question

Soo will rent a car for the weekend. She can choose one of two plans. The first plan has an initial fee of$44and costs an additional$0.14per mile driven. The second plan has an initial fee of$51and costs an additional$0.12per mile driven.
for what amount of driving would the 2 plans cost the same? how would i calculate that
and what is the cost when the 2 plans cost the same

Answer 1

Help someone how do I do this?

Answer 2

@surjithayer would 168 be the price for both

Answer 3

12x14=168 and 14x12=168

Answer 4

or would the cots be 1.68

Answer 5

im lost please someone

Answer 6

@One098 Can you help me please I'm lost

Answer 7

?

Answer 8

m stands for # of miles
44 + 0.14m = 51 + 0.12m --- set the 2 plans equal to each other
0.14m - 0.12m = 51 - 44 -- get the m terms on one side
0.02m = 7
m = 7/0.02
m = 350

The 2 plans will cost the same at 350 miles

check..
44 + 0.14(350) = 51 + 0.12(350)
44 + 49 = 51 + 42
93 = 93 (correct)

And when driving 350 miles, each plan costs $ 93

Answer 9

Thanks @texaschic101 a lil fast but i think i get it

Answer 10

one last question if u could help @texaschic101
To rent a certain meeting room, a college charges a reservation fee of
$48
and an additional fee of
$9.40
per hour. The math club wants to spend less than
$113.80
on renting the meeting room.

What are the possible amounts of time for which they could rent the meeting room?
Use
t
for the number of hours the meeting room is rented, and solve your inequality for
t
.

Answer 11

48 + 9.40t < 113.80
9.40t < 113.80 - 48
9.40t < 65.80
t < 65.80/9.40
t < 7

They can rent the room for anything UNDER 7 hrs

Answer 12

@texaschic101 can you explain that one more thoroughly

Answer 13

Let the distance driven be x miles in two plans.
44+0.14x=51+0.12x
0.14x-0.12x=51-44
0.02 x=7
\[x=\frac{ 7 }{ 0.02 }=7\times \frac{ 100 }{ 2 }=7\times50=350 miles\]

Answer 14

cost in each case\[=44+0.14 x=44+\frac{ 14 }{ 100 }\times350=44+49=393 $\]

Answer 15

correction 44+49=93 $