Question

How do you show work::
(6c^3-5)+(2c^3+8+3c^2)-(4c^2-7c-9)

Answer 1

\[(6c^3-5)+(2c^3+8+3c^2)-(4c^2-7c-9) \]

Answer 2

thats the equation it just makes it easier to read

Answer 3

Remove the parentheses that are not needed from the expression.
6c3−5+2c3+8+3c2−(4c2−7c−9)
Multiply −1 by each term inside the parentheses.
6c3−5+2c3+8+3c2−4c2+7c+9
Since 6c3 and 2c3 are like terms, add 2c3 to 6c3 to get 8c3.
8c3−5+8+3c2−4c2+7c+9
Add 8 to −5 to get 3.
8c3+3+3c2−4c2+7c+9
Add 9 to 3 to get 12.
8c3+12+3c2−4c2+7c
Since 3c2 and −4c2 are like terms, add −4c2 to 3c2 to get −c2.
8c3+12−c2+7c
Reorder the polynomial 8c3+12−c2+7c alphabetically from left to right, starting with the highest order term.
8c3−c2+7c+12

Answer 4

? why is it showing it

Answer 5

( 6c³ - 5 ) + ( 2c³ + 8 + 3c² ) - ( 4c² - 7c - 9 )

1) First clear the parentheses by distributing the + sign and the - sign.
After you have distributed, you will have this:
6c³ - 5 + 2c³ + 8 + 3c² - 4c² + 7c + 9

2) Combine like terms
After you have combined the terms with c³, the terms with c², and the number terms, you will get this:
It might be easier to group the like terms together, like this:
6c³ + 2c³ + 3c² - 4c² + 7c - 5 + 8 + 9
... 8c³ .......... - 1c² ...+ 7c ....... + 12 <-- answer

Answer:
8c³ - 1c² + 7c + 12