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Chemistry 7 Online
OpenStudy (darkigloo):

2Al + Fe2O3 -> Al2O3 + 2Fe How many moles of Fe2O3 are required to completely react with 41g Al?

sammixboo (sammixboo):

Poo can't help you there.. Sorry hun! \(\Huge \bbox[#008080, 2pt]{~~~~~~~~~~~~~~~}\Huge \bbox[#c9c9c9, 2pt]{~~~~~~~~~~~~~~~}\Huge \bbox[#008080, 2pt]{~~~~~~~~~~~~~~~}\) \(\Huge \bf \color{teal}{\color{#808080}{**~~~~~}*sammixboo*\color{#808080}{~~~**}}\) \(\Huge \bbox[#008080, 2pt]{~~~~~~~~~~~~~~~}\Huge \bbox[#c9c9c9, 2pt]{~~~~~~~~~~~~~~~}\Huge \bbox[#008080, 2pt]{~~~~~~~~~~~~~~~}\)

OpenStudy (darkigloo):

That's okay. :)

OpenStudy (preetha):

Start with Al. Convert it to moles. Then you need to write down the ratio between moles of Al used and moles of Fe2O3. You should be able to convert moles of Al to moles of Fe2O3. Try it.

OpenStudy (darkigloo):

Al is 1.52 moles. So do i divide it by 2?

OpenStudy (darkigloo):

@Preetha

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