acetic acid =4.76, ka=_________M
I'm cluless!
Sorry i have no idea
@ganeshie8 maybe?
I think it is... pH = 4.760 + log 0.00379/ 0.00621 = 4.55 Not really sure. It may be wrong though...
@Sepeario
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*YAWN* Huh? You woke me from my hibernation? Don't you see that I'm a wolf?
Sorry.
Does anyone know how to do this
You just woke up a wolf, man IDEK how to do this, google Helps.
acetic acid pKa=4.76, ka=_________M
Don't ask a wolf! Wolves only know about how to sleep, eat, hunt, howl, and.... other stuff. Not this, it's not important to our way of life.
You know that the pH = 2.88 pH = -log [H+] using log laws: [H+] = 10^-pH [H+] = 10^-2.88 [H+] = 1.318*10^-3 You know that : For acetic acid use HAc Ka = [H+] *[Ac]/ [HAc] you know [H+] = [Ac-] = 1.318*10^-3 . So [H+] * [Ac-] = [H+]² and [HAc] = 0.1 Substitute: Ka = (1.318*10^-3)²/0.1 Ka = 1.74*10^-6 / 0.1 Ka = 1.74*10^-5 pKa = -log Ka pKa = -log ( 1.74*10^-5) pKa = 4.76
@toxicsugar22 do u get that ??
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