Question

If the standard for is (x-13)^2 +(y-9)^2=121 the center of the circle is (15/2,9) the what is the radius of the circle?

Answer 1

please check the given.. 'cause if that's the equation, then you'll have (13,9) as the center of the circle..

Answer 2

the standard form for the equation of a circle is:
\[(x-h)^{2} + (y-k)^{2} = r ^{2}\]
where (h,k) is the center

Answer 3

on my homework i put (13,9)..heres the peoblem

Answer 4

by inspection, you'll find the radius as

Answer 5

since you already have (h,k) and r values, substitute them to the standard equation..

Answer 6

ok thx

Answer 7

Do you know the standard form?

Answer 8

by substituting the values you'll have:
\[(x - \frac{ 15 }{ 2 })^{2} + (y - 9)^{2} = 5.5^{2} \]
since 5.5^2 is 30.25, you may have it as 30.25

Answer 9

ahhh I see, ok thank you lots