Question

I am having trouble converting with bases. Can anyone help me with this and explain it better then the book. Convert a3 fourteen to a base six.

Answer 1

convert to base10 first

Answer 2

\[\large \left(A3\right)_{14} = 10\times 14^1 + 3\times 14^0 = \left(143\right)_{10}\]

Answer 3

convert base10 to base6

Answer 4

ok - I see how you converted to the base 10 and I understand that. Our book is not very good and does not give many examples.

Answer 5

good :) do you know how to convert it to base6 ?

Answer 6

I do not...but I am re-reading now on how to convert a base 10 to another base

Answer 7

its easy, you just need to count in powers of 6 : ... 6^3, 6^2, 6^1, 6^0

Answer 8

how many 6^3's are there in 143 ?

Answer 9

ok - I am following

Answer 10

in other words, how many times 6^3 goes in 143 ?

Answer 11

there are 0 6^3's in 143, right ?

Answer 12

would it be 78six?

Answer 13

it has to occupy more positions in base6

Answer 14

i mean it has to occupy atleast 3 digits in base6

Answer 15

ok - let me retry

Answer 16

103 six?

Answer 17

convert it to base10,
do u get 143 back ?