If f(x)=x4+2cos(x) / 2sin(x), find f′(π/2).
whats our derivative?
f(x) = 4x^3 + (-2sinx) (2sinx) + (x^4 +cosx) ( 2cosx) / 2sinx^2
f(x)=x^4+2cos(x) / 2sin(x) f(x)=x^4 csc(x) + cot(x) f(x)= 4x^3 csc(x) -x^4 cot(x)csc(x) - csc^2(x)
i forgot the /2 on the first term doh
\[f \left( x \right)=\frac{ x^4 +2\cos \left( x \right) }{ 2\sin \left( x \right) }\,\, \text{ or } f \left( x \right)= x^4 +\frac{2\cos \left( x \right) }{ 2\sin \left( x \right) }\]
f(x)= 2x^3 csc(x) -x^4 cot(x)csc(x)/2 - csc^2(x)
csc(pi/2) = sin(pi/2) = 1 sooo
isnt cot(pi/2) = 0 since its perp to a vertical slope?
i don't know much about trig
then youll need more practice. trig id 98% memorization
** trig is ....
why did you use csc?
tangent is the slope of a line thru the center of a circle .... pi/2 is 90 degrees is attributed to 1/0 cotangent is the reciprocal of tangent giving us 0/1
1/sin=csc
instead of the quotient rule, i just broke it all apart and used trig identities
okay thx i think i got it now!
yw, my work of it my have some errors so i hope you dont use it verbatim
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